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Simplifying 121 + -483x2 + -4x4 = 0 Solving 121 + -483x2 + -4x4 = 0 Solving for variable 'x'. Factor a trinomial. (1 + -4x2)(121 + x2) = 0 Factor a difference between two squares. ((1 + 2x)(1 + -2x))(121 + x2) = 0Subproblem 1
Set the factor '(121 + x2)' equal to zero and attempt to solve: Simplifying 121 + x2 = 0 Solving 121 + x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-121' to each side of the equation. 121 + -121 + x2 = 0 + -121 Combine like terms: 121 + -121 = 0 0 + x2 = 0 + -121 x2 = 0 + -121 Combine like terms: 0 + -121 = -121 x2 = -121 Simplifying x2 = -121 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.Subproblem 2
Set the factor '(1 + 2x)' equal to zero and attempt to solve: Simplifying 1 + 2x = 0 Solving 1 + 2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2x = 0 + -1 2x = 0 + -1 Combine like terms: 0 + -1 = -1 2x = -1 Divide each side by '2'. x = -0.5 Simplifying x = -0.5Subproblem 3
Set the factor '(1 + -2x)' equal to zero and attempt to solve: Simplifying 1 + -2x = 0 Solving 1 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2x = 0 + -1 -2x = 0 + -1 Combine like terms: 0 + -1 = -1 -2x = -1 Divide each side by '-2'. x = 0.5 Simplifying x = 0.5Solution
x = {-0.5, 0.5}
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